About Points
If you like the taste of dynamic geometry that you experience here, then contact AAMT about purchasing Cabri-Geometry II.
Construction method | Construction data | Description |
---|---|---|
free | integers x, y | a freely dragable point in the screen plane with initial coordinates (x,y,0) |
midpoint | points A, B | the midpoint of a line AB |
intersection | points A, B, C, D
[plane E] |
the intersection of two lines AB and CD in the plane E |
points B, C
plane A |
the intersection of the plane A and the line BC | |
first | points A, B | the first end A of the line AB |
last | points A, B | the last end B of the line AB |
center | circle A | the center of the circle A |
sphere A | the center of the sphere A | |
lineSlider | points A, B
integers x, y,[z] |
a point that slides along a line AB with initial coordinates (x,y,z) |
circleSlider | circle A
integers x, y,[z] |
a point that slides along a circle A with given initial coordinates (x,y,z) |
circumcenter | points A, B, C
[plane D] |
the center of a circle ABC passing through 3 points A, B, and C in the plane D |
vertex | polygon A
integer i |
a vertex Ai of the polygon A1A2...An with index i |
foot | points A, B, C | the foot of a perpendicular drawn from A to a line BC |
point A
plane B |
the foot of a perpendicular drawn from A to a plane B | |
cutoff | points A, B, C, D | the point E on a line AB so that AE = CD |
extend | points A, B, C, D | the point E on a line AB so that BE = CD |
parallelogram | points A, B, C | the 4th vertex D of a parallelogram ABCD given 3 vertices A, B, and C |
similar | points A, B, D, E, F
[planes C, G] |
the point H so that triangle ABH in plane C is similar to triangle DEF in plane G |
perpendicular | points A, B,
[plane C] |
the point D so that AD is equal and perpendicular to AB in plane C |
points A, B, D, E
[plane C] |
the point F so that AF is perpendicular to AB in plane C and equals DE | |
points A, C, D
plane B |
the point E on the line perpendicular to plane B passing through A so that the distance from E to B equals CD | |
proportion | 8 points A, B, C, D, E, F, G, H | the point I on GH so that AB:CD = EF:GI |
invert | point A
circle B |
the image of a point A inverted in the circle B |
meanProportional | 6 points A, B, C, D, E, F | the point G on EF so that AB:CD = CD:EG |
planeSlider | plane A
integers x, y, z |
a point that slides on the plane A with initial coordinates (x,y,z) |
sphereSlider | sphere A
integers x, y, z |
a point that slides on the sphere A with initial coordinates (x,y,z) |
angleBisector | points A, B, C
[plane D] |
The point at the intersection of the angle bisector of angle BAC and the line BC in plane D |
angleDivider | points A, B, C
[plane D] integer n |
The point E on the line BC so that angle BAE is the nth part of the angle BAC in plane D |
fixed | integers x, y, z | the fixed point with coordinates (x, y, z) |
lineSegmentSlider | points A, B
integers x, y,[z] |
a point that slides along within the line segment AB with initial coordinates (x,y,z) |
David E. Joyce
Department of Mathematics and Computer Science
Clark University
Worcester, MA 01610Email: djoyce@clarku.edu
My nonJava Homepage and my Java homepage